At new Moon, the Earth, Moon and Sun are in a line, as...

At new Moon, the Earth, Moon and Sun are in a line, as indicated in Figure 5. Find the net gravitational force exerted on (a) the Earth, (b) the Moon, and (c) the Sun. Sun Moon Earth FIGURE 5

Transcript

00:01 First consider subpart a.

00:02 If the equation for the gravitational force on earth, due to moon is given by fem is equal to gme -m -m divided by r -e -m -square.

00:17 Here, g is the universal gravitation constant.

00:20 M -e is the mass of the earth, m -m -m is the mass of the moon, and r -e -m -m is the distance between the earth and the moon.

00:28 Substituting the numerical values in the equation gives fem is equal to 6 .67 into 10 raise to minus 11 meter cube per kilogram second square into 5 .972 into 10 raised to 24 kilogram into 7 .35 into 10 raised to 22 kilogram divided by 3844.

01:02 Into 10 raised to 5 meter square, which is equal to 1 .98 into 10 raised to 20 newton.

01:14 Now, the equation for the magnitude of the gravitational force on earth due to sun is given by g m -e -m -s divided by r -e -s square.

01:28 Here, ms is the mass of the sun, and r -e -s is the distance.

01:33 Between the earth and the sun.

01:35 Substituting the numerical values in the equation gives, fes is equal to 6 .67 into 10 -res to minus 11 meter cube per kilogram second square into 5 .972 into 10 -res to 24 kilogram into 1 .9891 into 10 raised to 30 kilogram divided by 149 .1 into 10 raised to 9 meter square, which is equal to 3 .56 into 10 raised to 22 newton.

02:23 The gravitational force on earth due to moon acts towards the move and the gravitational force on earth due to the sun acts towards the sun.

02:33 This implies both of the forces are acting in the same direction.

02:38 Therefore, the equation for the net gravitational fourth on earth is given by fge is equal to fem plus fes.

02:49 Substituting the numerical values in the equation gives fge is equal.

02:53 To 1 .98 into 10 raise to 20 newton plus 3 .56 into 10 raised to 22 newton, which is equal to 3 .58 into 10 raise to 22 newton.

03:12 Therefore, the answer to subpart a is equal to 3 .58 into 10 raised to 22 newton.

03:19 Now consider subpart b.

03:23 The magnitude of the gravitational force on moon due to earth will be equal to the magnitude of the gravitational force on earth due to moon.

03:33 Therefore, fme is equal to 1 .98 into 10 raised to 20 newton...

Question

At new Moon, the Earth, Moon and Sun are in a line, as indicated in Figure 5. Find the net gravitational force exerted on (a) the Earth, (b) the Moon, and (c) the Sun. Sun Moon Earth FIGURE 5

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