29. At perihelion the planet Mars is at its closest to the sun, at a distance D = 2.06 × 10^{11}m. The sun has a diameter d = 1.39 × 10^9m. What is the angular size ? of the sun in the Martian sky? (From the Earth, the sun subtends about 0.5°.) A) ? = 0.00387° C) ? = 0.00675° E) ? = 0.535° B) ? = 0.00535° D) ? = 0.387° F) ? = 0.675°

          29. At perihelion the planet Mars is at its closest to the sun, at a distance D = 2.06 &times; 10^{11}m. The sun has a diameter d = 1.39 &times; 10^9m. What is the angular size ? of the sun in the Martian sky? (From the Earth, the sun subtends about 0.5°.)
A) ? = 0.00387° C) ? = 0.00675° E) ? = 0.535°
B) ? = 0.00535° D) ? = 0.387° F) ? = 0.675°

29. At perihelion the planet Mars is at its closest to the sun, at a distance D = 2.06 times; 10^11m. The sun has a diameter d = 1.39 times; 10^9m. What is the angular size ? of the sun in the Martian sky? (From the Earth, the sun subtends about 0.5°.)
A) ? = 0.00387° C) ? = 0.00675° E) ? = 0.535°
B) ? = 0.00535° D) ? = 0.387° F) ? = 0.675°

Added by Sandra N.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Penny Riley

08/01/2022

Step 1

39 \times 10^9}{2 \times 2.06 \times 10^{11}} = \frac{1.39 \times 10^9}{4.12 \times 10^{11}} = \frac{1.39}{4.12} \times 10^{-2} = 0.3374 \times 10^{-2} = 0.003374 \] ** Show more…

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At perihelion the planet Mars is at its closest to the sun, at a distance D = 2.06 × 10^{11}m. The sun has a diameter d = 1.39 × 10^9m. What is the angular size θ of the sun in the Martian sky? (From the Earth, the sun subtends about 0.5°.) A) θ = 0.00387° C) θ = 0.00675° E) θ = 0.535° B) θ = 0.00535° D) θ = 0.387° F) θ = 0.675°