Question

At some point along the direct path from the center of the Earth to the center of the Moon, the gravitational force of attraction on a spacecraft from the Moon becomes greater than the force from the Earth. A.) How far from the center of the Earth does this occur? B.) At this location, how far is the spacecraft from the surface of the Moon? How far is it from the surface of the Earth? Mass of Earth = 5.97 * 1024 kg Radius of Earth = 6.37 * 103 km Mass of Moon = 7.35 * 1022 kg or about 1/81 mass of Earth Radius of Moon = 1740 km

          At some point along the direct path from the center of the Earth to the center of the Moon, the gravitational force of attraction on a spacecraft from the Moon becomes greater than the force from the Earth.
A.) How far from the center of the Earth does this occur?
B.) At this location, how far is the spacecraft from the surface of the Moon? How far is it from the surface of the Earth?
Mass of Earth = 5.97 * 1024 kg
Radius of Earth = 6.37 * 103 km
Mass of Moon = 7.35 * 1022 kg or about 1/81 mass of Earth
Radius of Moon = 1740 km

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Added by Mark T.

University Physics with Modern Physics

Hugh D. Young 14th Edition

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Solved by Expert Shaiju T

05/06/2022

Step 1

674 * 10^-11 N(m/kg)^2), m1 and m2 are the masses of the two objects, r is the distance between the centers of the two objects. We are looking for the point where the gravitational force from the Earth (F_E) equals the gravitational force from the Moon (F_M). So Show more…

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At some point along the direct path from the center of the Earth to the center of the Moon, the gravitational force of attraction on a spacecraft from the Moon becomes greater than the force from the Earth. A.) How far from the center of the Earth does this occur? B.) At this location, how far is the spacecraft from the surface of the Moon? How far is it from the surface of the Earth? Mass of Earth = 5.97 * 1024 kg Radius of Earth = 6.37 * 103 km Mass of Moon = 7.35 * 1022 kg or about 1/81 mass of Earth Radius of Moon = 1740 km

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