00:01
Hi, in this question, the specific enthalpy of a fluid at the inlet of the nozzle is given as h1 is equal to 3 ,232 kilojoules per kg.
00:21
The velocity of fluid at the inlet is given as, let us say, c1 is given as 269 km per hour.
00:36
This must be converted into meters per second.
00:39
For that, kilometer into meter divided by 3 ,600.
00:44
On calculation, we obtained 74 .72 meters per second.
00:54
Then the enthalpy at the exit of the nozzle is given as h2 is equal to 2 ,526 kilojoules per kg.
01:12
The specific volume of the fluid at the exit of the nozzle, b2 is given as 0 .67 cubic meter per kg.
01:26
Then the specific volume at the inlet of the nozzle, v1 is given as 0 .34 cubic meter per kg.
01:46
Inlet area of the nozzle, a1 is given as 0 .2 square meter.
01:55
We need to determine exit area of the nozzle...