00:01
Hello, here we have to solve the following problem.
00:02
At the moment, which is 0 seconds, the car was traveling at a constant, at a speed of 20 meters per occurs under constant acceleration.
00:20
From the time interval, in the time interval from t2 of 2 .0 seconds to t3, which is 4 .00 seconds, the car traveled the distance of 56 meters and we have to calculate acceleration of the car.
00:43
Let's do this.
00:44
So here, x as a function of time equals to v0t plus a .t squared over 2.
00:53
So let's calculate x at the moment t2.
00:58
So that equals to v0 t plus 2 plus a2 plus a2 squared over 2.
01:13
And let's calculate x at the moment t3 that is v0t3 plus a t3 squared over 2.
01:23
Now let's calculate the distance d, which is the distance between x at t3 and t2.
01:30
And that is equals to v0 t3 plus a t3 squared over 2 minus v0 t2 minus a t squared over 2 that equals to v0 times t3 minus t 2 plus a over 2 times t3 squared or 2 so let's rearrange this equation...