Question

At time t = 0 a ball is thrown from an initial height h = 5.89 m with an initial velocity of magnitude v = 25.05 m/s making an angle ? = 49.5° above the horizontal. How far is the ball (along the horizontal) from its initial position when it hits the ground? Use g = 10 m/s². Round off your answer to 2 decimal places and do not write the unit.

Name: At time t = 0 a ball is thrown from an initial height h = 5.89 m with an initial velocity of magnitude v = 25.05 m/s making an angle ? = 49.5° above the horizontal. How far is the ball (along the horizontal) from its initial position when it hits the ground? Use g = 10 m/s². Round off your answer to 2 decimal places and do not write the unit.
Uploaded: 2023-07-19T05:21:09-08:00
Duration: 2 min 13 s
Channel: Madhur L
Description: At time t = 0 a ball is thrown from an initial height h = 5.89 m with an initial velocity of magnitude v = 25.05 m/s making an angle ? = 49.5° above the horizontal. How far is the ball (along the horizontal) from its initial position when it hits the ground? Use g = 10 m/s². Round off your answer to 2 decimal places and do not write the unit.

          At time t = 0 a ball is thrown from an initial height h = 5.89 m with an initial velocity of magnitude v = 25.05 m/s making an angle ? = 49.5° above the horizontal. How far is the ball (along the horizontal) from its initial position when it hits the ground? Use g = 10 m/s². Round off your answer to 2 decimal places and do not write the unit.

At time t = 0 a ball is thrown from an initial height h = 5.89 m with an initial velocity of magnitude v = 25.05 m/s making an angle ? = 49.5° above the horizontal. How far is the ball (along the horizontal) from its initial position when it hits the ground? Use g = 10 m/s². Round off your answer to 2 decimal places and do not write the unit.

Added by Angelica A.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Madhur L

07/19/2023

Step 1

First, we need to find the horizontal and vertical components of the initial velocity. The horizontal component of the initial velocity is given by $v_x = v \cos{\theta}$, and the vertical component is given by $v_y = v \sin{\theta}$. Show more…

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At time t = 0, a ball is thrown from an initial height h = 5.89 m with an initial velocity of magnitude v = 25.05 m/s, making an angle ̃́ = 49.5° above the horizontal. How far is the ball (along the horizontal) from its initial position when it hits the ground? Use g = 10 m/s². Round off your answer to 2 decimal places and do not write the unit.