Given acceleration, \(a_x = bt = 3t\) m/s^2
Integrate to find the velocity:
\[\int a_x dt = \int 3t dt\]
\[v = \frac{3}{2}t^2 + C\]
Given initial velocity at \(t = 0\), \(v_0 = 2\) m/s, we can find the constant \(C\):
\[v_0 = \frac{3}{2}(0)^2 + C\]
\[C =
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