00:01
Hello, and in this question here, we need to determine how many fusions per second we require in order to have a power plant of deuterium tritium fusion that outputs 1 ,000 megalletron watts, sorry, 1 ,000 megawatts.
00:17
So the total energy we need, okay, given that the efficiency, okay, so we have an efficiency of 33%.
00:26
So if we want to output 1 ,000, megawatts per megawatts that means that's only three thirty three percent of the energy you require because we're only 33 percent efficient so this means the total energy we will actually require is actually a thousand megawatts divided by point three three and that there will be the total energy will actually require okay so this is equal to three point zero three three times ten to the nine watts.
01:06
Okay, so that there, or watts, we can replace watts with joules per second.
01:10
So that's how much energy per second we're going to need for, we're going to need from our nuclear reactions.
01:18
Okay.
01:19
Now, this energy, okay, will be equal to the energy released in each nuclear reaction.
01:26
So we're going to use e -subscript r multiplied by the number of reactions per second.
01:31
So this means the number of reactions per second is, which is what we're trying to find.
01:36
Is equal to 3 .0303 times 10 to the 9 joules per second divided by the energy released in a reaction.
01:47
Now, what is the energy released in the reaction? so our reaction is we have a hydrithrithium plus deuterium becoming a helium 4 and a neutron.
02:00
So, sorry, that's helium 4 and a neutron.
02:03
Okay? so, the energy released, how we're going to calculate this, well, energy is conserved.
02:09
So the energy released will be equal to the energy difference in the rest mass energy of the final state and of the initial state...