00:01
Hello student, so in this question the acceleration of the electron is f equals to qe so here may equals to qe so so a y equals to q so here m a y equals to qe so here ay is equal to qe so here a y is equal to qe divided by m so here the initial speed of the proton is 0 in the direction of electric field when it isn't moving perpendicular in the electric field.
00:38
So here, v -o -y is equal to 0.
00:42
So the time taken travel the electron through the field is t equals to x divided by vx.
00:53
So here x is 2 multiplied by 10 power minus 2 meter divided by vx.
01:00
X is 1 .80 multiply by 10 power 6 so here t will come 1 .11 multiply by 10 power minus 8 second now the displacement of the electron so here the displacement the displacement of the electron in y -axis direction is as yy equals to v -o -y t plus half a y t square so here v o y is zero plus half a y is q e divided by m t square so here s y is one multiply by ten power minus two divided by two equals to half q e m t divided by m multiplied by t square.
02:10
So here, e equals to m 1 multiply by 10 power minus 2 divided by qt square.
02:23
So here, e equals to m is 1 multiply by 10 power minus 2, m is 9 .11 multiply by 10 power minus 1 ,000, divided by 1 .6 multiplied by 10 power minus 19 multiply by 1 .11 multiplied by 10 power 8 square.
02:52
So here when we calculated we get e equals to 462 .11 1 .1 w per meter...