00:01
Okay, so we have an atwood's machine, we're given the masses, we know little g is 9 .8 meters per second squared.
00:07
I'm going to choose the acceleration so that m1 is falling while m2 is rising.
00:15
And we know that we have essentially a perfect pulley, massless and frictionless, and the is inextensible so the accelerations are the same on both sides.
00:30
We don't have to worry about other stuff.
00:36
M1 is heavier so just intuition tells us that's the one that's going to be going down while m2 is going up.
00:45
So let's draw a free body diagram.
00:47
So here's m1, we got tension pointing up, m1g pointing down, the acceleration is pointing down.
00:58
So newton's second law tells us t minus m1g is minus m1a.
01:08
And then the second free body diagram, t pointing up, m2g pointing down, and then here the acceleration is pointing up so we get t minus m2g is equal to m2a...