00:01
We would like to draw the circuit.
00:03
So here we have a circuit of a three cells in series.
00:08
Here are three cells, each with a value of 2v, 2v, and 2v, with internal resistance of 0 .5 oms.
00:18
So all of these have an internal resistance of 0 .5 oms, connected to a 2 oms resistor in series, which is this one, and our combination of 2, 3 -oam resistors.
00:31
We're asked to find the effective external resistance.
00:35
So our effective external resistance, r, is equal to our 2 omega plus 3 omega and parallel with the 3 omega.
00:45
So this is equal to 2 plus 3 times 3 divided by 3 plus 3, or 3 .5 oms.
00:56
So our internal resistors are in a serious combination.
01:01
So our internal resistance, total internal resistance, is equal to 1 .5 oms...