00:01
We are given the difference in lengths, difference in lengths that is equal to l2 minus l1 that is given as 0 .04 centimeter.
00:16
And the initial temperature, initial temperature t1 is given as 10 degrees centigrade and the final temperature, final temperature, final temperature, t2 is given as 30 degree centigrade.
00:33
So during this time period during this temperature change the change in length occurs 0 .04 centimeter and we are given the coefficient of linear expansion alpha that is to multiply 10 to the power minus 5 per degree centigrade now we are going to find the initial length l0 or we can say the length at 0 degree centigrade so, initial length l0 at 0 degree centigrade we are going to find.
01:13
Now, we are going to use the equation l1 equal to l0 1 plus alpha and change in temperature delta t1.
01:24
That means from 0 to 10 degree centigrade.
01:28
So delta t1 comes out to be 10 degree centigrade.
01:32
So, l1 equal to l0 1 plus alpha is 2 multiplied 10 to the power minus 5 multiply 10, or it comes out to be l0 1 plus 20 multiplied 10 to the power minus 5...