00:01
For the given problem, the value of impedance in series is given as 0 .08 00 plus j times 0 .4 ome per kilometer and the value of y percent is equal to j 30 multiplied to 10 percent of s that is a total.
00:24
So this will be equal to 30 multiplied to 10 to the power minus 5 angle 90 degree.
00:30
So we can say that the value of length of transmission line will be equal to 100 km and the value of z total will be equal to 0 .08 j 0 .4 multiplied to 100 om so this will be equal to 8 plus j 40 om and thus this will be equal to 40 .79 angle 78 .69 degrees.
01:00
So if we are considering the pi model, so we can say that that.
01:03
This matrix a, b, c, d will be equal to 1 plus 1 plus yz upon 2.
01:13
This is z and this will be equal to y1 plus y2 upon 4.
01:19
This will be 1 plus yz upon.
01:22
So because over here we have considered a2p 1 plus y z upon 2.
01:28
So we can say that this will be equal to 1 plus 30 multiplied to 10 to 0 minus 5 angle 90.
01:35
Multiply to 40 .79 angle 78 .69 divided upon 2 this will be equal to 0 .994 angle 0 .069 degrees so the value of b will be equal to z so this will also be equal to 40 .79 angle 78 .69 degrees for c for the value of c we will have for the value of c we will have y 1 plus y 2 upon 4 thus this will be equal to 30 multiplied to 10 to the power minus 5 angle 90 and this will also be equal to 1 plus 30 multiplied to 10 to minus 5 angle 90 0 .79 angle 78 .69 degree upon 4 and this will be equal to 2 .99 multiply to 10 to the power minus 4 angle 90 .03 similarly for d we will have equal to a that will be equal to 0 .994 angle 0 .069 degree now for the first part we can say that the value of zl will be equal to 240 angle 36 .9 degrees and the value of y shunt will be equal to j 30 multiplied to 10 % of s total thus the receiving voltage vr will be equal to 230 kilowolts and the value of i r will be equal to vr 12 that is 230 multiplied to 10 to the power 3 angle 0 degree divided upon 240 angle 36 .9 degree on solving we'll have 958 .8.
03:18
Angular minus 36 .9 kilo ampere sending end voltage sending and voltage will come out to be a vr that is 0 .99 angular 0 .069 degree multiplied to 230 angle 0 plus 40 .79 angle 0 plus 40 .79 angle 6 .7 9.
03:38
78 .69 multiplied to 0 .958 ankle minus 36 .9 degree.
03:46
Thus on solving we'll have 259 .0 .0 angular 5 .82 degrees kilowolt.
03:53
Similarly, we can have vs l minus l that will be equal to square root of 3...