00:01
The error estimated by the bi -section method, the ets, is equal to b negative a over 2 to the power of n, where the given interval, that is a, comma, b is equal to 0 .1.
00:24
So, but we need to the error, error ets should be less than equal to 10 to the power of negative 7.
00:34
So it implies b negative a over 2 to the power of n should be less than equal to 10 to the power of negative 7.
00:44
Now substitute the value of b and a here, that is 1 negative 0 over 2 to the power of n should be lessen equal to 10 to the power of negative 7.
00:57
So it implies 1 over 2 to the power of n should be less than equal to 10 to the bar of negative 7.
01:05
Take the natural log on both sides, that is the natural log of 1 over 2 to the bar of n less than equal to the natural log of 10 to the bar of negative 7...