00:01
Hi everyone, so in the question we have to give here a carbon cycle and at the initial position in the carbon cycle pressure is 10 .5 atmosphere and the temperature is t1 is equal to 500.
00:15
Okay, so in the first step there is isothermal expansion and after the isothermal expansion there is tension is equal to 1 atmosphere and then there is in the second step and the wetting expansion their temperature will be equal to to 350 carbon and then asothermal then aerobatic and then it goes to the initial and this is a reversible carbonoc cycle okay so what we have to find out we have to find out the value of k -turro -thruderloo h or s here okay so first of all in the process in asothermal expansion okay so in arso -dermal expansion we know that change in internal energy is equal to telethylase is equal to zero okay this is the case of isothermal isothermal techniques the temperature will be same and the temperature will be same than the changing internal energy will be zero here okay so in iso thermal expansion we know that the work done is equal to minus m r t l m bf 35 bf that that is final volume 25 initial and this will be equal to minus n r d l n that means low down cell okay and this will be equal to b f 25 p that means b2 25 p okay, so by putting the values of these terms, we know that minus n even in the portion we have, this is equal to one more.
01:51
Okay, this is even in the portion, yes, it is spent here, okay, and the value of r, r, if a value is 8 .1 per calorie per number.
02:05
Okay, this is the value of r .h.
02:08
And the temperature is 7 ,2, is that it 500 kelvin, okay, so we know to age.
02:14
Okay and this is multiplied by the term ln p225 p5p 5 temperature is 1 .00 and the initial pressure is 10 .5 okay, dividing and the look at this term we go that this is equal to 97 .7 .740.
02:41
Okay and the whole term is in minus here.
02:44
Okay, so this is the value of work done here in the isoterm in expansion.
02:50
So after this term, we quote that q is equal to here, r is equal to limit that the changing internal energy is equal to minus of tuckl.
02:59
So this is equal to 97 .7 of kilo -chrome.
03:04
This is the value 8 -0 to the system.
03:09
Okay, so this is the value of 8 -kero system.
03:13
Okay.
03:13
Then in the second term, it is saying that we have to find out changing in terms of the changing entropyl and we know that the change in entropy is equal to minus n r lm p225 this is the formula of changing entropy okay so by putting the value of all the terms minus 1 0 0 mon okay and by reply this term by a 1c1 and by my plan's term by allen 1 .0035 10 .0 .0.
03:53
Okay, so by solving these people, that this is 1.
04:06
So this is the whole term that is equal to this here.
04:09
Okay, so we know that the total internal energy of the system, that is total, total energy of the system, is always equal to less than that is internal energy of the system.
04:23
Of system plus there has no change in the energy of this.
04:29
Okay, this is the sum of all these two terms.
04:35
So you know that the change in total energy of the system and frowning it always is 1 to 0...