0:00
Hi.
00:01
Here in this given problem, first of all there is part b of the problem in which inductance of an inductor coil that is given as 40 .0 millie henry and capacitance of the capacitor.
00:19
This is 600 pico ferret.
00:23
And here we have to find resonant frequency of this circuit taking its resistance to be negligible.
00:31
Small so that resonant frequency here is given as it is given by the formula f0 is equal to 1 by 2 pi into square root of the product of l with c so plugging in all the known values here this is 2 into 3 .14 square root of 40 into 10 dash per minus 3 into 600 into 10 dash per minus 12 so here it may be written as 6 .28 into square root of 24 into 10 to the power minus 12.
01:21
And finally, it is solved to get 3 .25 into 10 raised to the power 4 hertz.
01:35
This is the answer for the part b of this given problem here.
01:40
Then there is part c of the problem which is having so many parts in its subparts.
01:52
And it says in rlc series circuit resistance, the value of resistance is 5 .6 kiloom.
02:09
Self -inductance is 40 millie henry and capacitance is 600 micro -farrate.
02:17
Frequency of the ac applied is 75 hertz and rms voltage applied that is 24 volt in the first part of this problem we have to find angular frequency simply that will be given by 2x into f so this is 2 into 3 .14 into frequency that is 75 so it comes out to be equal to 471 radian per second.
03:02
Answer for the first part of the problem.
03:08
Then in the second part of the problem, we have to find inductive reactance of the circuit.
03:19
Inductive reactance means opposition offered in the path of ac by inductor coil...