Question

k B DQ cs1 ns1 Tc=5 Td=10 ns0 For the above diagram: • 10 ps is the delay for each gate. • 25 is the contamination minimum. • 200 is the propagation maximum. Part 1: What is the contamination delay from the output of A to the input of B Part 2: What is the propagation delay from the output of A to the input of B Part 3: The holding time for the circuit is 50 ps. Does the circuit work or is it in hazard? A DQ cs0 Tc=5 Td=10

          k
B
DQ
cs1
ns1
Tc=5
Td=10
ns0
For the above diagram:
•
10 ps is the delay for each gate.
•
25 is the contamination minimum.
•
200 is the propagation maximum.
Part 1:
What is the contamination delay from the output of A to the input of B
Part 2:
What is the propagation delay from the output of A to the input of B
Part 3:
The holding time for the circuit is 50 ps. Does the circuit work or is it in hazard?
A
DQ
cs0
Tc=5
Td=10

k
B
DQ
cs1
ns1
Tc=5
Td=10
ns0
For the above diagram:
•
10 ps is the delay for each gate.
•
25 is the contamination minimum.
•
200 is the propagation maximum.
Part 1:
What is the contamination delay from the output of A to the input of B
Part 2:
What is the propagation delay from the output of A to the input of B
Part 3:
The holding time for the circuit is 50 ps. Does the circuit work or is it in hazard?
A
DQ
cs0
Tc=5
Td=10

Added by Gabriel A.

University Physics with Modern Physics

Hugh D. Young 14th Edition

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Texts: B cs1 Tc=5 Td=10 ns1 nso A cs0 Tc=5 Td=10 For the above diagram, 10 ps is the delay for each gate. 25 is the contamination minimum. 200 is the propagation maximum. Part 1: What is the contamination delay from the output of A to the input of B? Part 2: What is the propagation delay from the output of A to the input of B? Part 3: The holding time for the circuit is 50 ps. Does the circuit work or is it in hazard?