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Hello students welcome.
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In this question we have given a diamond which is having a diamond is having the density of 3 .51 grams per ml is given and the mass of one carbon atom.
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So mass of one carbon atom is given as 1 .994 multiplicity.
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Multiplied by 10 -pore minus 8 fematograms is given.
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And also we have the number of carbon atoms that are present in diamond is given.
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So number of carbon atoms present in the diamond is equal to 3 .0 to 10th power 6 atoms.
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Okay, so we have to calculate the volume of diamond.
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So volume of diamond should be calculated here.
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So we know the mass of the diamond.
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So mass of diamond is equal to the number of carbon atoms, 3 .02 multiplied by 10 power 6 and it is multiplied by 1 .994 into 10 power minus 8, fematograms okay so this is equal to 0 .0602 fematograms okay so this approximately 0 .0602 fematograms then it is it should be converted to grams that's why we will multiply this one with 10 power minus 15 so one phmetograph is equal to 10 power minus 15...