B. For the given rectifier output voltage, find the average...

B. For the given rectifier output voltage, find the average value of each voltage. [3 marks] 5 V 0 V Figure 12 +25 V 0 V -15 V Figure 13 20 V 10 V 0 V Figure 14 100 V 0 V Figure 15 10 A. In below given diodes circuit with V1=3V, R= 1k?, RL=670?, (Assume Diodes used are Ge). [2 Marks] Determine the following: a. Voltage across the load resistor RL. b. Current flowing through R. Figure 16

Transcript

00:01 Hi, in the first part of the question we are given with a figure so voltage curve.

00:04 So in the first question the voltage is discrete.

00:07 So this is here we have the value of v average is given by it is 1 by t integration 0 to t by 2 vm of sin omega t into dt.

00:20 So this becomes equal to v average is equal to vm by pi.

00:25 So here the maximum voltage or peak voltage is given as 5 volt divided by pi.

00:32 So we have the answer for average voltage is 1 .59 volt.

00:36 Then in the second diagram again we have the value of v average is given by it is 2 by t into so 0 to t by 2 into sin omega t into vm into dt minus 50 because there is an 82 voltage also included.

00:57 Therefore this becomes equal to it is 2 vm divided by t minus 15 which is equal to 2 into 25 plus 5.

01:05 So peak voltages vary from 25 and 15 divided by pi minus 15.

01:10 So from this we have the average voltage is equal to 10 .6 so 10 .46 volt.

01:18 Then in the third part we are given with full wave rectifier.

01:22 So where we have v average is given by it is 10 volt plus 2 by t integration 0 to t by 2 vm into sin omega t dt.

01:33 So this can be written as it is 10 plus 2 vm by pi.

01:38 So this is 10 plus 2 into so vm varies from so vm has voltage 10 ohm therefore it is 2 into 10 divided by pi.

01:52 So this is equal to so v average is equal to 16 .36 volt.

01:58 Then for the fourth part we have full wave rectifier.

02:02 So full wave rectifier where we are given with a value of v average as it is 2 by t integration 0 to t by 2 vm sin omega t into dt.

02:15 So this becomes equal to it is 2 by t into vm so vm by pi which is equal to so this is 2 vm by pi.

02:25 So this is equal to it is 2 into so voltage is 100 divided by pi...

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