Question

b) If an enantiomeric mixture contained a ratio of R:S of 23:77 and displays a specific rotation of -22° what is the specific rotation of the pure R enantiomer under the same conditions? (1 point)

          b) If an enantiomeric mixture contained a ratio of R:S of 23:77 and displays a specific rotation of -22° what is the specific rotation of the pure R enantiomer under the same conditions?
(1 point)

Added by Zachary R.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert Adi S

07/20/2023

Step 1

The total number of parts is 23 + 77 = 100. The fraction of R enantiomer is $\frac{23}{100} = 0.23$. The fraction of S enantiomer is $\frac{77}{100} = 0.77$. Show more…

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b) If an enantiomeric mixture contained a ratio of R:S of 23:77 and displays a specific rotation of -22° what is the specific rotation of the pure R enantiomer under the same conditions? (1 point)