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a. $H_0: P_1 - P_2 = 0$ $H_a: P_1 - P_2 \neq 0$ Sample 1 Sample 2 $n_1 = 374$ $n_2 = 400$ $x_1 = 172$ $x_2 = 183$ Let $\alpha = .05$. Note that x is the number in the sample having the characteristic of interest. b. $H_0: P_1 - P_2 = 0$ $H_a: P_1 - P_2 > 0$ Sample 1 Sample 2 $n_1 = 659$ $n_2 = 559$ $\hat{P}_1 = 0.36$ $\hat{P}_2 = 0.25$ Let $\alpha = .10$. Appendix A Statistical *(Round the intermediate values to 3 decimal places, e.g. 1.254. Round your answer to 2 decimal places, e.g. 15.25.) **(Round the intermediate values to 2 decimal places, e.g. 15.25. Round your answer to 2 decimal places, e.g. 15.25.) a. Observed z = The decision is to fail to reject the null hypothesis

          a. $H_0: P_1 - P_2 = 0$  $H_a: P_1 - P_2 \neq 0$
Sample 1
Sample 2
$n_1 = 374$
$n_2 = 400$
$x_1 = 172$
$x_2 = 183$
Let $\alpha = .05$.
Note that x is the number in the sample having the characteristic of interest.
b. $H_0: P_1 - P_2 = 0$  $H_a: P_1 - P_2 > 0$
Sample 1
Sample 2
$n_1 = 659$
$n_2 = 559$
$\hat{P}_1 = 0.36$
$\hat{P}_2 = 0.25$
Let $\alpha = .10$.
Appendix A Statistical
*(Round the intermediate values to 3 decimal places, e.g. 1.254. Round your answer to 2 decimal places, e.g. 15.25.)
**(Round the intermediate values to 2 decimal places, e.g. 15.25. Round your answer to 2 decimal places, e.g. 15.25.)
a. Observed z = 
The decision is to fail to reject the null hypothesis

a. H0: P1 - P2 = 0 Ha: P1 - P2 ≠ 0
Sample 1
Sample 2
n1 = 374
n2 = 400
x1 = 172
x2 = 183
Let α = .05.
Note that x is the number in the sample having the characteristic of interest.
b. H0: P1 - P2 = 0 Ha: P1 - P2 > 0
Sample 1
Sample 2
n1 = 659
n2 = 559
P̂1 = 0.36
P̂2 = 0.25
Let α = .10.
Appendix A Statistical
*(Round the intermediate values to 3 decimal places, e.g. 1.254. Round your answer to 2 decimal places, e.g. 15.25.)
**(Round the intermediate values to 2 decimal places, e.g. 15.25. Round your answer to 2 decimal places, e.g. 15.25.)
a. Observed z =
The decision is to fail to reject the null hypothesis

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