Question

(b) Suppose exactly one child is a girl. (That Is, Event \( Y \) occurs.) This will limit the possible outcomes. From the remaining outcomes, check the outcomes for Event \( X \). Then, enter the probability that Event \( X \) occurs given that Event \( Y \) occurs. \begin{tabular}{|c|c|c|c|c|c|c|} \hline & \multicolumn{5}{|l|}{Outcomes given exactly one child is a girl} & \multirow[t]{2}{*}{Probability} \\ \hline & BBG & BGB & GBB & . & & \\ \hline Event X: The last child is a boy & \( \square \) & \( \checkmark \) & \( \square \) & & & \( \frac{2}{3} \) \\ \hline \end{tabular} (c) Give the following probabilities and select the correct option below. \[ \begin{array}{c} \frac{P(X \text { and } Y)}{P(Y)}=\square \\ P(X \mid Y)=\square \\ \frac{P(X \text { and } Y)}{P(Y)} ? P(X \mid Y) \end{array} \] Explanation Check Desk 1

          (b) Suppose exactly one child is a girl. (That Is, Event \( Y \) occurs.) This will limit the possible outcomes. From the remaining outcomes, check the outcomes for Event \( X \). Then, enter the probability that Event \( X \) occurs given that Event \( Y \) occurs.
\begin{tabular}{|c|c|c|c|c|c|c|}
\hline & \multicolumn{5}{|l|}{Outcomes given exactly one child is a girl} & \multirow[t]{2}{*}{Probability} \\
\hline & BBG & BGB & GBB & . & & \\
\hline Event X: The last child is a boy & \( \square \) & \( \checkmark \) & \( \square \) & & & \( \frac{2}{3} \) \\
\hline
\end{tabular}
(c) Give the following probabilities and select the correct option below.
\[
\begin{array}{c}
\frac{P(X \text { and } Y)}{P(Y)}=\square \\
P(X \mid Y)=\square \\
\frac{P(X \text { and } Y)}{P(Y)} ? P(X \mid Y)
\end{array}
\]
Explanation
Check
Desk 1

(b) Suppose exactly one child is a girl. (That Is, Event Y occurs.) This will limit the possible outcomes. From the remaining outcomes, check the outcomes for Event X. Then, enter the probability that Event X occurs given that Event Y occurs.

5|l|Outcomes given exactly one child is a girl [t]2*Probability

BBG BGB GBB .

Event X: The last child is a boy □ □ (2)/(3)

(c) Give the following probabilities and select the correct option below.

(P(X and Y))/(P(Y))=□

P(X | Y)=□
(P(X and Y))/(P(Y)) ? P(X | Y)

Explanation
Check
Desk 1

Added by Tammy J.

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