00:01
Hello students, consider the reaction c5h12 plus 8o2 is 5 co2 plus 6h2o first of all let's find out the number of moles of c5h12 number of moles of c5h12 is equal to given mass of c5 h12 which is 5 gram divided by molar mass of cipher h12 which is 72 .15 grams per mole.
00:45
This is equal to 0 .069 mole.
00:54
Now let's find out the number of moles of o2.
01:01
Number of moles of o2 is equal to given mass of o2 which is 10 gram divided by molar mass of o2 which is 32 grams per mole which is equal to 0 .313 mole.
01:32
From the reaction we can understand that 1 mole of c5h12 needs 8 mole of 0 2.
01:52
So 0 .069 mole of c5 h12 needs 8 into 0 .069 mol of c5 h12 needs 8 into 0 .069 0 .0 which is equal to 0 .552 mole of o2.
02:31
But the actual number of modes of o2 present is 0 .313 which is less than 0 .552 mole.
02:40
So the limiting reagent is o2.
02:54
Now we can write 8 .152.
02:59
So the limiting reagent is o2.
02:59
8 mole of o2 produces 5 mole of co2...