Question

(b) Use the table from part (a) to find the following probabilities. (ii) the probability that a randomly selected customer purchases an extended warranty for neither the washer nor the dryer We will use the table created in part (a) to find the probability that a randomly selected customer purchases an extended warranty for neither the washer nor the dryer. To do so we can use the following formula. \[ \begin{aligned} P(\text { purchased a warranty for neither } W \text { nor } D) & =P(\text { not } W \cap \text { not } D) \\ & =\frac{\text { number who purchased a warranty for neither } W \text { nor } D}{\text { total number of customers }} \end{aligned} \] Recall the table created in part (a). \begin{tabular}{|c|c|r|r|} \hline & D & Not D & Total \\ \hline W & 600 & 90 & 690 \\ \hline Not W & 140 & 170 & 310 \\ \hline Total & 740 & 260 & 1,000 \\ \hline \end{tabular} According to the table, the number of customers who purchased a warranty for neither the washer nor the dryer is \( \square \) . As previously determined, the total number of customers is 1,000 . Use these values to calculate the desired probability. \[ \begin{aligned} P(\text { purchased a warranty for neither } W \text { nor } D) & =P(\text { not } W \cap \text { not } D) \\ & =\frac{\text { number who purchased a warranty for neither W nor } D}{\text { total number of customers }} \\ & =\square \\ & =\square \end{aligned} \] SUBMIT SKIP (YOU CANNOT COME BACK)

          (b) Use the table from part (a) to find the following probabilities.
(ii) the probability that a randomly selected customer purchases an extended warranty for neither the washer nor the dryer

We will use the table created in part (a) to find the probability that a randomly selected customer purchases an extended warranty for neither the washer nor the dryer. To do so we can use the following formula.
\[
\begin{aligned}
P(\text { purchased a warranty for neither } W \text { nor } D) & =P(\text { not } W \cap \text { not } D) \\
& =\frac{\text { number who purchased a warranty for neither } W \text { nor } D}{\text { total number of customers }}
\end{aligned}
\]

Recall the table created in part (a).
\begin{tabular}{|c|c|r|r|}
\hline & D & Not D & Total \\
\hline W & 600 & 90 & 690 \\
\hline Not W & 140 & 170 & 310 \\
\hline Total & 740 & 260 & 1,000 \\
\hline
\end{tabular}

According to the table, the number of customers who purchased a warranty for neither the washer nor the dryer is \( \square \) . As previously determined, the total number of customers is 1,000 . Use these values to calculate the desired probability.
\[
\begin{aligned}
P(\text { purchased a warranty for neither } W \text { nor } D) & =P(\text { not } W \cap \text { not } D) \\
& =\frac{\text { number who purchased a warranty for neither W nor } D}{\text { total number of customers }} \\
& =\square \\
& =\square
\end{aligned}
\]
SUBMIT
SKIP (YOU CANNOT COME BACK)

(b) Use the table from part (a) to find the following probabilities.
(ii) the probability that a randomly selected customer purchases an extended warranty for neither the washer nor the dryer

We will use the table created in part (a) to find the probability that a randomly selected customer purchases an extended warranty for neither the washer nor the dryer. To do so we can use the following formula.

P( purchased a warranty for neither W nor D) =P( not W ∩ not D)
=( number who purchased a warranty for neither W nor D)/( total number of customers )

Recall the table created in part (a).

D Not D Total

W 600 90 690

Not W 140 170 310

Total 740 260 1,000

According to the table, the number of customers who purchased a warranty for neither the washer nor the dryer is □ . As previously determined, the total number of customers is 1,000 . Use these values to calculate the desired probability.

P( purchased a warranty for neither W nor D) =P( not W ∩ not D)
=( number who purchased a warranty for neither W nor D)/( total number of customers )
=□
=□

SUBMIT
SKIP (YOU CANNOT COME BACK)

Added by Lisa B.

Question

Please give Ace some feedback