B.25 2-Propylbut-1-ene is an incorrect name under the IUPAC...

B.25 2-Propylbut-1-ene is an incorrect name under the IUPAC system. What is the correct name for this compound? Hint: Draw the structure based on the incorrect name and rename it. B.26 Draw the structures for these molecules. (a) 2-chloropropene; (b) 3-methylbut-1-ene; (c) 2,3-dimethyl-2-butene; (d) 2-ethoxy-3,3-dimethylcyclohexene; (e) 3,4,5-trimethoxycycloheptene; (f) 3-bromo-2-methyl-4-nitrocyclopentene; (g) 3,3-dibromo-4-methylcyclopentene; (h) 4-methyl-2-pentyne B.27 Write the IUPAC name for each of the following molecules. (a) (b) (c) (d) (e) (f) (g) (h) (i)

Transcript

00:01 Hi, in this question 25th number there is a compound given two profile bute 1 in so according to the question this naming is incorrect and we have to draw the structure and write the correct i bac name for this compound so let's first draw the structure so bute means there are four carbons four carbons 1 2 3 and 4 these are the 4 carbons and 1 in is there is double bond in the first position then in the second position there is two propile propile means three carbon probes so this will be ch2 ch2 ch3 and now balancing so this will be ch2 this will be ch2 this will be ch2 this will be ch3 so this compound will be two propyl but one but one in but this is the incorrect naming so the correct naming will be one two three four five because the longest chain will be this.

01:11 This will be the longest chain, 5 carbon chain.

01:14 And in this case, the correct timing will be 2 -ethyl, sorry, 2 -ethyl, pent, 1 -ene.

01:27 So this will be the correct nomenclature according to the iupac.

01:30 2 -ethyl, pent -1 -ane.

01:33 Then, 26th number question, we have to draw the structure of the given molecules.

01:38 A is 2 -chloropropine.

01:44 Chloropine.

01:45 Again, propine means there are three carbons.

01:48 So 1, 2 and 3 carbons.

01:50 Then in the second position there is chloro and propine and there is double bond in the first position.

01:58 So this will be ch2 and this will be ch3...

Question

Please give Ace some feedback