Question

b. In an experiment to measure the acceleration g due to gravity, two values, 9.96 m/s² and 9.72 m/s², are determined. Find (1) the percent difference of the measurements, (2) the percent error of each measurement, and (3) the percent error of their mean. The accepted value for g is 9.80 m/s². (show work!!) % difference % error 1 % error 2 % error of mean

          b. In an experiment to measure the acceleration g due to gravity, two values, 9.96 m/s²
and 9.72 m/s², are determined. Find (1) the percent difference of the measurements,
(2) the percent error of each measurement, and (3) the percent error of their mean.
The accepted value for g is 9.80 m/s².
(show work!!)

% difference
% error 1
% error 2
% error of mean

b. In an experiment to measure the acceleration g due to gravity, two values, 9.96 m/s²
and 9.72 m/s², are determined. Find (1) the percent difference of the measurements,
(2) the percent error of each measurement, and (3) the percent error of their mean.
The accepted value for g is 9.80 m/s².
(show work!!)

% difference
% error 1
% error 2
% error of mean

Added by Jose Ramon C.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Khoobchandra Agrawal

09/14/2022

Step 1

- Percent Difference = (|9.96 - 9.72| / ((9.96 + 9.72) / 2)) * 100% - Percent Difference = (0.24 / 9.84) * 100% - Percent Difference = 2.44% ** Show more…

Show all steps

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b. In an experiment to measure the acceleration g due to gravity, two values, 9.96 m/s^2 and 9.72 m/s^2, are determined. Find (1) the percent difference of the measurements, (2) the percent error of each measurement, and (3) the percent error of their mean. The accepted value for g is 9.80 m/s^2. (show work!!) % difference % error 1 % error 2 % error of mean