00:01
Okay, so we need to balance this redox reaction in both acidic and basic conditions.
00:04
So the first thing we need to do is we need to find the charge on each of the different atoms.
00:11
So here for this first one, our charge on the oxygen is negative 2.
00:17
On the chromium, so that would be a total of negative 14.
00:21
This is going to be a total of positive 12, so the chromium is 6.
00:24
Here each o is negative 2.
00:27
Chlorine is 3.
00:28
Chromium is plus 3 as we're told o is negative 2 and chlorine is going to be 5 so chromium goes from 6 to 3 and chlorine goes from 3 to 5 so looking at our dichromate cr 2 o 7 going to see our 3 plus first we need to make sure we have the same number on each side so we'll put a 2 in front of that chromium then to go from a six to a three is three electrons and we have to do that twice because there's two chromiums then we need to balance out our oxygen so i need to add seven waters to the right and then 14 hydrogen ions to the left next we need to do our clo2 going to clo3 so it's going from three to five or five to three so i'll add two electrons to the right then i need to add one one water to the left to balance out the oxygens.
01:29
And then i need two hydrogen ions.
01:31
Next, i need to cancel out my electrons.
01:35
So the electrons will be gone here.
01:38
And then i have 14 hydrogens and six hydrogens, three times two.
01:44
So these will all be gone and i'll be left with eight.
01:47
And then i have six, excuse me, three waters and seven waters.
01:52
So so these will all be gone and i'll be left with four waters.
01:56
So the overall equation is going to be 8h plus plus cr2o7 2 minus plus 3clo2 minus goes to 2cr3 plus plus 3clo3 minus plus 4h2o...