00:01
We are asked to balance this redox in acidic solution.
00:06
So i'm going to start by separating this into my oxidation reduction reactions.
00:18
My oxidation will be the i2 going to the io3.
00:24
Let's go ahead and do this.
00:26
That's io3 minus.
00:27
So i'm going to have to put a two here, add six waters to this side, add six hydrogens to this side, and that's going to give me five electrons on that side.
00:50
No, that's, i did that wrong.
00:56
There's 12 hydrogens here, 12, and that gives me 12 and two, so that would be 10.
01:02
There we go.
01:05
And next i've got my pbo2 and my pb2 plus.
01:12
So this will need a couple waters on this side, four hydrogens on this side.
01:20
Then i've got two pluses.
01:28
I'll need two electrons on this side.
01:32
Let me see.
01:33
That one looks pretty good.
01:34
That one looks pretty good...