00:02
Hi there, in this question we are asked to balance this chemical equation.
00:08
Well balancing means that we add coefficients, which are numbers that go in front of the terms, so that, so we add these as needed so that we end up with the same number of each type of atom on each side of the equation.
00:22
And coefficients have to be whole numbers, we can't have a fraction of a of an atom or a molecule.
00:30
Okay so basically balancing is just some educated logic when we are balancing, it's kind of an educated trial and error.
00:42
So let's start off just with the first thing we come to which is calcium, and there are three calcium on the left and only one calcium on the right.
00:50
That means i have to add a three in front of casio3 so that i have three calcium.
00:59
Next i want to look at the phosphorus.
01:05
Well there are two phosphorus on the left and you see there's four on the right.
01:10
Well to fix that, that means i need to put a two in front of this entire term, because two times two would give us four phosphate.
01:21
All right but by doing that now i have changed the calcium.
01:26
There's two times three or six calcium.
01:29
So i need to come back to my right side and add a six.
01:33
Did i mention when balancing it's very useful to use a pencil with an eraser because you are going to be going back and forth sometimes.
01:41
All right i want to save the oxygen for later because oxygen appears in several terms.
01:49
So next i'm going to go to the si.
01:51
I have six si on the right side so i'm going to put a six in front of sio2 on the left to give me six si.
02:00
All right now let's go ahead and focus on those oxygen.
02:05
In the calcium phosphate i have two times two which is four times four which is 16 total oxygen...