00:02
Let's balance the equation in the question 49 in basic solutions.
00:06
So for a, we've got ag solid, n .o3 minus aqueous to ag plus aqueous, and ano -g -plus aqueous, and an -o -gas.
00:23
Let's split this up into two separate half -reactions.
00:26
We have ag -solid to ag -plus aqueous.
00:30
Balance this.
00:31
We need an electron on the right.
00:32
And we have n -o -3 -1 -aquius, anal -gas.
00:39
Two waters to balance the oxygen atoms, 4h plus to balance the hydrogen atoms, three electrons to balance the charge.
00:53
I'll triple this one here, electrons would cancel, and we would be left with 3g solid, nl3 -3 -1, 4h plus, 3a2, n0 gas, 2h2l liquid.
01:16
Now this is balanced in acidic conditions, so to switch it to basic, we're going to cancel out to 3g plus.
01:25
The h plus ions, simplify the waters, two, and in basic conditions we'd have 3hb solid, n03 minus 2h2o to produce 3av plus, no gas, and 4 oh h minus...