00:01
The reaction that has been given to us is sodium carbonate is reacting with calcium, calcium chloride to form calcium carbonate and sodium chloride.
00:17
So this currently this reaction is not balanced.
00:20
So we will first balance the equation.
00:22
Now we will see that on the left side there are two sodium atoms, one carbon atom, three oxygen atom, one calcium.
00:31
Atom and two chlorine atoms whereas on the right hand side there is one calcium one carbon one three oxygen one sodium atom and one chlorine atom so first we can balance we can start by balancing the chlorine atoms so we will multiply the right -hand side chlorine atoms with two so on multiplying chlorine with two automatically the sodium will also get multiplied by two and we will get the stoichiometric coefficient two beside nacl now to now we can see that any sodium atoms on the left inside is two carbon is one oxygen is three calcium is one and chlorine is two atoms and on the right side also the number of atoms is same so now we can say that this equation has been balanced and the balanced equation will again be represented as n .a .2 co3 plus calcium chloride to give caco3 plus 2 naccl.
01:47
So this is the balanced equation.
01:53
Now it has been given that we have 0 .5 gram of n .a .2 co3 and calcium chloride is in excess.
02:01
So we can say that this will be the limiting reactant which will determine the amount of nacl that will be produced.
02:13
So first we have to calculate the number of moles of n .a2 co3 from 0 .5 gram...