For example: 2 H2(g) + 1 O2(g) ? 2 H2O(l) [ ] K3PO4(aq) + [...

For example: _ 2_ H2(g) + _1_ O2(g) ? _2_ H2O(l) [ ] K3PO4(aq) + [ ] BaCl2(aq) ? [ ] KCl(aq) + [ ] Ba3(PO4)2(s) [ ] MnO2(s) + [ ] CO(g) ? [ ] Mn2O3(aq) + [ ] CO2(g) [ ] C4H10(g) + [ ] O2(g) ? [ ] CO2(g) + [ ] H2O(l) [ ] NO2(g) + [ ] H2O(l) ? [ ] HNO3(aq) + [ ] NO(g) [ ] CoBr3(aq) + [ ] Pb(NO3)2(aq) ? [ ] Co(NO3)3(aq) + [ ] PbBr2(s)

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Transcript

00:01 Here in this problem we have to balance these equations using the smallest whole number coefficient.

00:08 Now, here we see 3 barium atoms on the both sides, sorry on the right side of the equation.

00:17 So to balance the number of barium atoms let us place 3 here.

00:22 Now we have 3 barium atoms on the both sides of the equation.

00:27 Now we have 3 times 2, 6 chlorine atoms.

00:30 So here we place 6.

00:33 Now we have 6 chlorine atoms on the both sides of the equation.

00:37 Here we have 6 potassium atoms.

00:40 So to balance the number of potassium atoms let us place 2 here.

00:43 Now we have 6 k atoms on the both sides of the equation.

00:48 2 po4, here also 2 po4.

00:51 So this equation is balanced.

00:54 The next one, here we see mn2o3 and here we will place 2.

01:05 So we have 2 mn atoms on the both sides of the equation.

01:09 Now we have 2 times 2, 4 plus 1, 5 oxygen atoms and here on the right side also 3 plus 2, 5 oxygen atoms and 1 carbon atoms on the both sides of the equation.

01:24 So this equation is also balanced.

01:26 The next one c4h10 plus o2 gives 8 co2 plus h2o.

01:33 Now here we have 4 carbon atoms.

01:37 So let us place 4 here.

01:39 Now we have 4 carbon atoms on the both sides of the equation.

01:44 Here we have 10 hydrogen atoms.

01:47 So let us place 5 here...

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