00:01
Hello everyone, let's start the question.
00:03
In this question we are asked to balance the following given equation in which mn 04 negative is changing to mn2 positive in acidic solution.
00:17
So acidic solution implies that we are balancing in acidic medium.
00:24
We have to carry out the steps for balancing the above equations in acidic medium.
00:33
So let's start the balancing one by one by following the step.
00:39
So in the first step if we write the skeletal equation that we have is mno4 negative changes to mn2 positive.
00:49
So now in this case first of all we will be balancing balance the oxygen atom as we can see that on left -hand side we have four numbers.
01:02
We have four number of oxygen atom whereas there is no oxygen atom present on the right end side of the equation so whenever we are carrying out the balancing in acidic medium what is the key step to balance the oxygen atom wherever there is less number of oxygen atom we add that much number of water molecules and in the opposite direction we add the double of it the h plus ion so let's write so that it becomes clear how we are doing it this mno 4 negative remains as it is.
01:37
We are going to add 4 water molecules onto the right hand side of the equation in order to balance the oxygen.
01:48
So now oxygen has become equal but there is no hydrogen present on the left side.
01:54
So in order to balance the hydrogen we will be adding 8 times of h plus ions...