1) First, we need to balance the given redox reaction under acidic conditions:
$$\text{MnO}_4^-(\text{aq}) + \text{CH}_3\text{OH}(\text{aq}) \rightarrow \text{HCO}_2\text{H}(\text{aq}) + \text{Mn}^{2+}(\text{aq})$$
Balancing the redox reaction, we
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