00:01
In this problem, balance the redox reaction.
00:05
So, acidic solution, this is the, for acidic solution, this is the equation given to us, right? okay.
00:18
So this reaction occur, a reaction occur in acidic medium, right? all right.
00:28
So the balanced redox reaction will be what? this will be equals to v2 plus plus of two times of, v -o -h whole 4 you can say oh whole 4 plus plus sign plus 2h plus that gives us 3 vo 2 plus plus 5 h2o isn't it so this is the balanced redox reaction right so this was for the first one right so now now we can see that the oxidation for if we see the second equation right so this is for the first part all right see this is for the first part and the second part we can see that c roh is thrice plus h2 that is giving us c r o 4 2 minus plus 5 h plus 3 electrons right so this is the oxidation now in reduction process we can see that h2o2 is getting under reduction.
01:55
So this is h2 plus two electrons that gives us 2 oh minus right.
02:01
So this is supposed to be second equation.
02:03
So oxidation is first equation and reduction of the second compound is represented at second equation...