Balance these half-reactions and state whether they are...

Balance these half-reactions and state whether they are Oxidation or Reduction. Ru2O3 ? RuO3 SO42- ? SO2 HIO3 ? I3- N2O ? NO2 Balance these equations using the half-reaction method we learned in class. Al + Mg2+ ? Mg + Al3+ SO4 + CH4 ? SO2 + CO2 PH3 + ClO3- ? P4 + Cl2 (in acidic solution) MnO4- + CrO2 ? CrO42- + MnO2 (in basic solution)

Transcript

00:01 Hello, in this question here we need to balance this half cell reaction.

00:05 So here first we have that is ru -2 -3 and it will produce this ru -o -3.

00:12 So here this balanced reaction, that is we have this ru -2 -3 which is having this plus 3 oxidation state.

00:21 On adding this 3h2o, we will have 2ru -3 plus 6 -h proton it is this.

00:30 Here it is having this plus 3 oxidation state and plus 6 oxidation state it is there so therefore here in this case this is plus 3 to plus 3 that means 3 loss of electron it is so therefore here to this oxidation process it is there oxidation that means lossing of electron next we have from s o 4 minus 2 to s o 2 so here we need to balance this so therefore the balance reaction here as 0 4 minus 2 plus 4h positive plus 2 electron and it produced here that is so2 plus 2h2 plus 2h2 here this sulphur it is having this plus 6 oxidation state and here it is plus 4 that means gaining of 2 electron in this case so therefore this process it is reduction process now in the next we have h i o3 2 we have this i 3 negative so therefore here if you balance this equation we have 3 h i o 3 plus 16 electron here plus 15 proton and it is producing this i 3 negative and to maintain this we have 9 h2 o so here for this i it is having this plus 5 oxidation state and here we have this minus 1 so this plus 5 to minus 1 so this plus 5 to minus 1 that means 4 electrons have been gained so this process is reduction process now in the next part we have this n2 o it is getting converted to n o 2 so here this n2 o plus h2 it produce 2 moles of n o 2 plus 2h positive so here this n2 it is having this plus 1 and here it is having plus 2.

02:39 That means one electron have been lost in this case.

02:42 So therefore here this process is oxidation process.

02:48 Now for the next part we are given here this redox reaction and here we need to balance those reactions.

02:56 This redox reaction which consists of reduction plus oxidation reaction.

03:05 So here we have the reaction that is in the first case we have a reduction...

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