00:01
So here it is given that a ball is thrown above into the horizontal with some angle.
00:05
Let's suppose the angle is to be theta here.
00:09
And having the initial velocity of 20 meter per second.
00:16
Now ball covers a distance of 10 meter.
00:20
So we have to calculate the maximum height of the arc through which the ball travels is.
00:26
So first of all, let us talk about the king concept here.
00:29
So let's suppose this is nothing but what the starting point, this is the end point.
00:33
Now ball is thrown from this point to this point, let's say from a to b with some angle making with horizontal, that is theta, and its initial velocity, let's say, is u, which we have given here as 20 meter per second.
00:51
Now if you see, it's covered 10 meter of distance.
00:55
That means we are given a a to b distance of about.
00:59
10 meter which we generally denote it as the range covered by the ball right so if you see this is what the maximum point that that the ball will cover so generally if we try to calculate the vertical height of it so its vertical height will be nothing but the maximum height covered by the ball okay so first of all if you see we need to find this angle theta here for which i will use the formula of range that is r is given by r equals to u square sine 2 theta divided by g...