Question

A ball falls from height of 19.5 m, hits the floor, and rebounds vertically upward to height of 15.5 m. Assume that m_ball = 0.400 kg. (a) What is the impulse (in kg · m/s) delivered to the ball by the floor? magnitude kg · m/s direction (b) If the ball is in contact with the floor for 0.0400 seconds, what is the average force (in N) the floor exerts on the ball? magnitude N direction

          A ball falls from height of 19.5 m, hits the floor, and rebounds vertically upward to height of 15.5 m. Assume that m_ball = 0.400 kg.
(a) What is the impulse (in kg · m/s) delivered to the ball by the floor?
magnitude kg · m/s
direction
(b) If the ball is in contact with the floor for 0.0400 seconds, what is the average force (in N) the floor exerts on the ball?
magnitude N
direction

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A ball falls from height of 19.5 m, hits the floor, and rebounds vertically upward to height of 15.5 m. Assume that mball = 0.400 kg.
(a) What is the impulse (in kg · m/s) delivered to the ball by the floor?
magnitude kg · m/s
direction
(b) If the ball is in contact with the floor for 0.0400 seconds, what is the average force (in N) the floor exerts on the ball?
magnitude N
direction

Added by Jared T.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Prabhu Ramji

07/12/2022

Step 1

We can use the equation of motion: v^2 = u^2 + 2gs, where v is the final velocity, u is the initial velocity, g is the acceleration due to gravity (9.8 m/s^2), and s is the displacement. When the ball falls from a height of 19.5 m, its initial velocity (u) is 0, Show more…

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A ball falls from height of 19.5 m, hits the floor, and rebounds vertically upward to height of 15.5 m. Assume that m_ball = 0.400 kg. (a) What is the impulse (in kg · m/s) delivered to the ball by the floor? magnitude: kg · m/s direction: (b) If the ball is in contact with the floor for 0.0400 seconds, what is the average force (in N) the floor exerts on the ball? magnitude: N direction:

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