Question

1. A balloon filled with helium has a volume of 4.0 x 10³ L at 25° C. What volume will the balloon occupy at 50° C if the pressure surrounding the balloon remains constant? a. 1.35 x 10³ L b. 430 L c. 4.3 x 10³ L d. 2.00 x 10?³ L 2. What is the volume (L) occupied by a mole of an ideal gas, if the pressure is 626 mmHg and the temperature is 25.0°C? a. 29.7 L b. 3.28 x 10?³ L c. 2.97 L d. 5.66 L

          1. A balloon filled with helium has a volume of 4.0 x 10³ L at 25° C. What volume will the balloon occupy at 50° C if the pressure surrounding the balloon remains constant?

a. 1.35 x 10³ L
b. 430 L
c. 4.3 x 10³ L
d. 2.00 x 10?³ L

2. What is the volume (L) occupied by a mole of an ideal gas, if the pressure is 626 mmHg and the temperature is 25.0°C?

a. 29.7 L
b. 3.28 x 10?³ L
c. 2.97 L
d. 5.66 L

1. A balloon filled with helium has a volume of 4.0 x 10³ L at 25° C. What volume will the balloon occupy at 50° C if the pressure surrounding the balloon remains constant?

a. 1.35 x 10³ L
b. 430 L
c. 4.3 x 10³ L
d. 2.00 x 10?³ L

2. What is the volume (L) occupied by a mole of an ideal gas, if the pressure is 626 mmHg and the temperature is 25.0°C?

a. 29.7 L
b. 3.28 x 10?³ L
c. 2.97 L
d. 5.66 L

Added by Josefa M.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert Madhur L

08/18/2023

Step 1

We can rearrange this equation to solve for V2: V2 = (P1V1T2)/(P2T1) Plugging in the given values, we get: V2 = (4.0*10^5 Pa * 1.35*10^-3 m^3 * 323 K)/(5.0*10^5 Pa * 298 K) = 1.47*10^-3 m^3 = 1.47 L So the volume occupied by the balloon at 50°C is 1.47 L. Show more…

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A balloon filled with helium has a pressure volume surrounding it of 4.0 * 10^5 Pa. The balloon will occupy a volume of 1.50 L if the pressure remains constant. What volume will the balloon occupy at 25.0°C? The volume occupied by a mole of an ideal gas can be calculated using the formula V = nRT/P, where V is the volume, n is the number of moles, R is the ideal gas constant, T is the temperature in Kelvin, and P is the pressure. Using this formula, the volume occupied by a mole of gas at 25.0°C can be calculated as follows: V = (1 mole * 8.314 J/(mol*K) * (25.0 + 273.15) K) / (626 mmHg * 133.322 Pa/mmHg) V = 0.00328 L Therefore, the volume occupied by a mole of gas at 25.0°C is 0.00328 L.