00:01
Hello student in this question it is asked that there are two balloons in one balloon one and balloon two it is said that in the balloon one the volume is 4 .50 liter this is the v that is the volume that is the volume and the pressure pressure is equals to 1 .6 to atm and it is said that the mass is equals to 1 .21 gram of helium is present and similarly in the balloon 2 there is 39 .69 gram of xenon is present and the volume and the pressure are same now we know the universal gas law pv equals to n r t where you see the p and v over here.
01:16
And what is t? t is the temperature temperature and r is the gas constant gas constant and n is the moles of the gas present.
01:37
So, in this question you can see the pressure and the volume is same and there are two balloons.
01:44
So we can write down p1 v1 divided by n1 t1 which is for the balloon 1 is equal to p2 v2 divided by n2 according to the question p1 is equal to p2 and v1 is equals to v2 so we can cancel these two things or we can write down n1 t1 is equals to n to t2 again you can see that the temperature is not mentioned so we can omit the temperature so the temperature thing is also omitted so, what we are getting, n1 and n2 thing.
02:36
Now, we have to find out this n1 or n2 is equal or not.
02:41
How we will find out? you can see, it is said that helium and xenon gas is present.
02:49
So, for helium, the atomic mass is 4 grams equals to 1 mole.
02:56
So in the question it is said that 1 .21 gram will be 1 .21 divided by 4 that is equals to 0 .3025 moles.
03:10
Again, if you see the xenon, it will be the atomic mass is 2 gram is equals to 1 mole.
03:19
And in the question it is mentioned that 39 .69 gram will be equals to 1 .3 .69 gram will be equals to 39 .69 divided by 131 .2 that is equals to 0 .3025 moles...