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Ba(OH)2 (aq) + H2SO4 (aq) BaSO4 (s) + 2H2O (l) What would you multiply grams of barium hydroxide by to convert to the units moles of sulfuric acid? (Number) (Unit) (Number) (Unit) grams Ba(OH)2 moles H2SO4 (Unit) (Number) (Unit) (Number)

Transcript

00:02 Hi there, in this question we want to convert from grams of the barium hydroxide to moles of the sulfuric acid.

00:13 So we're given our balanced equation.

00:15 I have omitted the states of matter because they're not necessary for a stoichiometry problem, which is what this one is, because we're trying to convert from information about one substance in the equation to information about something else.

00:31 Okay, so if we start with grams of barium hydroxide, what we first need to do is to convert to moles of the barium hydroxide, and we can do that by using barium hydroxide's molar mass, which is the mass in grams of one mole of the substance.

00:48 We determine that molar mass by using masses from the periodic table.

00:53 So one barium, two oxygen, and two hydrogen.

00:55 We have those masses all together to get that molar mass.

00:59 Then we can convert from moles of the barium hydroxide to moles of sulfuric acid by using the mole ratio.

01:13 The mole ratio comes to us from coefficients in the balanced equation.

01:18 Well, what we see here is there's no coefficient written in front of barium hydroxide or the sulfuric acid.

01:26 Therefore, we know that it's a one -to -one ratio.

01:30 When coefficients aren't written, it's understood that they're ones.

01:34 So we have a one -to -one mole ratio here.

01:36 Okay, so this is our plan.

01:38 Let's go ahead and set this up...