$\bar{x} = 15.963$ $\bar{y} = 1.263$ $S_{XX} = 141.319$ $S_{YY} = 4.988$ $S_{XY} = 20.76$ $MSE = 0.0692$ $\sqrt{MSE \times [\frac{1}{n} + \frac{(x^* - \bar{x})^2}{S_{XX}}]}$ $\sqrt{MSE \times [1 + \frac{1}{n} + \frac{(x^* - \bar{x})^2}{S_{XX}}]}$ $\hat{y} = b_0 + b_1x$
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The least squares estimate of the slope is given by $b_1 = \frac{S_{XY}}{S_{XX}}$. $b_1 = \frac{20.76}{141.319} = 0.1469$ The least squares estimate of the intercept is given by $b_0 = \bar{y} - b_1\bar{x}$. $b_0 = 1.263 - 0.1469 \times 15.963 = 1.263 - 2.345 = Show more…
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