Based on an analysis of sample data, an article proposed the pdf f(x) = 0.55e^-0.55(x - 1) when x ? 1 as a model for the distribution of X = time (sec) spent at the median line. (Round your answers to three decimal places.) (a) What is the probability that waiting time is at most 9 sec? More than 9 sec? at most 9 sec P(X ? 9) = 0.98772 more than 9 sec P(X > 9) = 0.1228 (b) What is the probability that waiting time is between 7 and 9 sec?
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The pdf given is \(f(x) = 0.55e^{-55x}\), and we are asked to find the probability that the waiting time is between 0 and 9 seconds. This involves integrating the pdf over the interval from 0 to 9. Show more…
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