Question

Based on an analysis of sample data, an article proposed the pdf $f(x) = 0.45e^{-0.45(x - 1)}$ when $x ge 1$ as a model for the distribution of X = time (sec) spent at the median line. (Round your answers to three decimal places.) (a) What is the probability that waiting time is at most 4 sec? More than 4 sec? at most 4 sec $P(X le 4) =$ more than 4 sec $P(X > 4) =$ (b) What is the probability that waiting time is between 3 and 9 sec?

          Based on an analysis of sample data, an article proposed the pdf $f(x) = 0.45e^{-0.45(x - 1)}$ when $x ge 1$ as a model for the distribution of
X = time (sec) spent at the median line. (Round your answers to three decimal places.)
(a) What is the probability that waiting time is at most 4 sec? More than 4 sec?
at most 4 sec  $P(X le 4) =$
more than 4 sec  $P(X > 4) =$
(b) What is the probability that waiting time is between 3 and 9 sec?

Based on an analysis of sample data, an article proposed the pdf f(x) = 0.45e^-0.45(x - 1) when x ge 1 as a model for the distribution of
X = time (sec) spent at the median line. (Round your answers to three decimal places.)
(a) What is the probability that waiting time is at most 4 sec? More than 4 sec?
at most 4 sec P(X le 4) =
more than 4 sec P(X > 4) =
(b) What is the probability that waiting time is between 3 and 9 sec?

Added by Purificaci-N F.

Elementary Statistics a Step by Step Approach

Allan G. Bluman 9th Edition

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Solved by Expert Supreeta N

10/15/2023

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45e^{-0.45x}, for x ≥ 0 1) Show more…

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Based on an analysis of sample data, an article proposed the PDF f(x) = 0.45e^(-0.45x) for x ≥ 1, representing the time (in seconds) spent at the median line. (Round your answers to three decimal places.) What is the probability that the waiting time is at most 2 seconds? More than 2 seconds? At most 4 seconds (P(X ≤ 4))? More than 4 seconds (P(X > 4))? What is the probability that the waiting time is between 2 and 4 seconds?