00:01
Fellow students given that a basketball player has made 60 % of his foul shots.
00:06
So that means probability of probability of foul shots foul shots is equal to 60 % that is 0 .60.
00:19
So therefore we can write probability of good shot probability of good shot is equal to 1 -0 .60 which is equal to 0 .40.
00:34
So therefore suppose this is denoted by p which is 0 .40 that is the probability of good shot.
00:43
Now, also we have given that the shots are independent and we have to find the probability that in tonight's game the basketball player misses for the first time on its sixth attempt.
00:59
So in the sixth attempt he misses the shot for the first time.
01:05
So therefore probability of misses for first time first time on the sixth attempt sixth attempt.
01:24
Now this probability is nothing but 1 -p raised to 5 into p.
01:32
So this is equal to 1 -0 .4 raised to 5 into 0 .4 which is equal to now this is 0 .6 raised to 5 into 0 .4 which is equal to 0 .0311.
01:54
Then in the b part we have to calculate the probability that basketball player makes his first basket on his fourth shot...