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be stopped by' are: sheet of paper, household wall or lead barrier 9. Suppose the amount of a certain radioactive substance in a sample decays from \( 3.80 \mathrm{mg} \) to \( 1.70 \mathrm{mg} \) over a period of 4.61 seconds. Calculate the half-life of the substance. Round your answer to 2 significant digits. \[ \ln \left(\frac{N}{N_{0}}\right)=-k t \quad k=\frac{\ln 2}{t_{1 / 2}} \] 10. A \( 500 \mathrm{~mL} \) flask is filled with \( 0.20 \mathrm{~mol} \) of \( \mathrm{NO}_{2}, 0.10 \mathrm{~mol} \) of \( \mathrm{NO} \) and \( 0.90 \mathrm{~mol} \) of \( \mathrm{CO}_{2} \). The following reaction becomes possible in the mixture: \[ \mathrm{NO}_{2}(\mathrm{~g})+\mathrm{CO}(\mathrm{g}) \leftrightarrow \mathrm{NO}(\mathrm{g})+\mathrm{CO}_{2}(\mathrm{~g}) \] The equilibrium constant \( K \) for this reaction is 7.25 at the temperature of the flask. Calculate the equilibrium molarity of NO. Round your answer to two decimal places.

          be stopped by' are: sheet of paper, household wall or lead barrier
9. Suppose the amount of a certain radioactive substance in a sample decays from \( 3.80 \mathrm{mg} \) to \( 1.70 \mathrm{mg} \) over a period of 4.61 seconds. Calculate the half-life of the substance. Round your answer to 2 significant digits.
\[
\ln \left(\frac{N}{N_{0}}\right)=-k t \quad k=\frac{\ln 2}{t_{1 / 2}}
\]
10. A \( 500 \mathrm{~mL} \) flask is filled with \( 0.20 \mathrm{~mol} \) of \( \mathrm{NO}_{2}, 0.10 \mathrm{~mol} \) of \( \mathrm{NO} \) and \( 0.90 \mathrm{~mol} \) of \( \mathrm{CO}_{2} \). The following reaction becomes possible in the mixture:
\[
\mathrm{NO}_{2}(\mathrm{~g})+\mathrm{CO}(\mathrm{g}) \leftrightarrow \mathrm{NO}(\mathrm{g})+\mathrm{CO}_{2}(\mathrm{~g})
\]

The equilibrium constant \( K \) for this reaction is 7.25 at the temperature of the flask. Calculate the equilibrium molarity of NO. Round your answer to two decimal places.

be stopped by' are: sheet of paper, household wall or lead barrier
9. Suppose the amount of a certain radioactive substance in a sample decays from 3.80 mg to 1.70 mg over a period of 4.61 seconds. Calculate the half-life of the substance. Round your answer to 2 significant digits.

ln((N)/(N0))=-k t k=(ln 2)/(t1 / 2)

10. A 500 mL flask is filled with 0.20 mol of NO2, 0.10 mol of NO and 0.90 mol of CO2. The following reaction becomes possible in the mixture:

NO2( g)+CO(g) ↔NO(g)+CO2( g)

The equilibrium constant K for this reaction is 7.25 at the temperature of the flask. Calculate the equilibrium molarity of NO. Round your answer to two decimal places.

Added by Keiara T.

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