Be sure to answer all parts. How many moles and numbers of ions of each type are present in the following aqueous solution? 306 mL of 0.355 g aluminum sulfate/L: mol of aluminum $\times$ 10 aluminum ions mol of sulfate $\times$ 10 sulfate ions
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To do this, we need to use the formula: moles = mass / molar mass The molar mass of aluminum sulfate (Al2(SO4)3) is: 2(Al) + 3(S) + 12(O) = 2(26.98 g/mol) + 3(32.07 g/mol) + 12(16.00 g/mol) = 342.15 g/mol Now we can calculate the number of moles of aluminum Show more…
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