00:01
Hi, in this question we are given with an acid -based reaction and we are asked to calculate the mass of the reactants such as k -o -h and h -3 -b -o -4, for which the mass of k -3 -p -o -4 and unreacted h -3 -p -o -4 is given in the question.
00:19
By using the mass of k -3 -p -o -4, we can calculate moles of k3po4.
00:26
Moles of k -3 -o -4 is equal.
00:33
To mass divided by molar mass.
00:44
The mass is 56 .3 grams divided by the molar mass of k3po4 is 212 .27 gram per mole.
01:01
On calculation we get 0265 mole.
01:10
By striketometry we can say that 1 mole of k3 pofor produced by 3 moles of k -o -h.
01:32
We can use unitary method for this calculation.
01:39
Therefore, 0 .265 mole of k3po4 produced by 3 into 0 .265 moles of kov.
02:05
Koh on multiplication we get moles of kohs equals to 0 .795 mole now we can calculate mass of koh since it is equal to mole into molar mass we are having the mole value that is 0 .795 mole into molar mass of k -o -h is 56 .1 gram per mole...