Question

Beang proset = (78 kN) / ((1.2 × 1.2) m^2) = 54.16 kPa prcsuta N78L Beon'y 2x1.2m P = 78 kN 500 mm Square ftg 1.200 mm 500 mm F 54.16 kPa 1 1.0 m //teams.microsoft.com/v2/ 14/16 OneNote Cc!+e = 0.13 C(i+e) = 0.04 m = 300 kPa = 18.0 kN/m Elorpe 8.7 1.0 m V N9 S9 hg = 1.2m x/m Beamy onstud 1.5 m Silty Clay Cc/(1+e) = 0.13 3.5 m C/(1+e) = 0.04 = 17.8 kN/m^3 2.0 m fFnd C md comyarc if fo Clay Cc/(1+e) = 0.15 C/(1+e) = 0.05 = 400 kPa = 19.0 kN/m^3 3.0 m

Name: beang proset 78 kn 12 12 m2 5416 kpa prcsuta n78l beony 2x12m p 78 kn 500 mm square ftg 1200 mm 500 mm f 5416 kpa 1 10 m teamsmicrosoftcomv2 1416 onenote cce 013 cie 004 m 300 kpa 180 knm el 23677
Uploaded: 2023-10-17T05:17:29-08:00
Duration: 1 min 9 s
Channel: Adi S
Description: beang proset 78 kn 12 12 m2 5416 kpa prcsuta n78l beony 2x12m p 78 kn 500 mm square ftg 1200 mm 500 mm f 5416 kpa 1 10 m teamsmicrosoftcomv2 1416 onenote cce 013 cie 004 m 300 kpa 180 knm el 23677

          Beang proset = (78 kN) / ((1.2 × 1.2) m^2) = 54.16 kPa

prcsuta N78L Beon'y 2x1.2m P = 78 kN 500 mm Square ftg 1.200 mm 500 mm F 54.16 kPa 1 1.0 m //teams.microsoft.com/v2/ 14/16

OneNote Cc!+e = 0.13 C(i+e) = 0.04 m = 300 kPa = 18.0 kN/m Elorpe 8.7 1.0 m V N9 S9 hg = 1.2m x/m Beamy onstud 1.5 m Silty Clay Cc/(1+e) = 0.13 3.5 m C/(1+e) = 0.04 = 17.8 kN/m^3 2.0 m fFnd C md comyarc if fo Clay Cc/(1+e) = 0.15 C/(1+e) = 0.05 = 400 kPa = 19.0 kN/m^3 3.0 m

beang proset 78 kn 12 12 m2 5416 kpa prcsuta n78l beony 2x12m p 78 kn 500 mm square ftg 1200 mm 500 mm f 5416 kpa 1 10 m teamsmicrosoftcomv2 1416 onenote cce 013 cie 004 m 300 kpa 180 knm el 23677

Added by Michael P.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Adi S

10/17/2023

Step 1

2m, the area can be calculated as: Area = length x width Area = 2m x 1.2m Area = 2.4 m^2 Show more…

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Beang proset = (78 kN) / ((1.2 × 1.2) m^2) = 54.16 kPa prcsuta N78L Beon'y 2x1.2m P = 78 kN 500 mm Square ftg 1.200 mm 500 mm F 54.16 kPa 1 1.0 m //teams.microsoft.com/v2/ 14/16 OneNote Cc!+e = 0.13 C(i+e) = 0.04 m = 300 kPa = 18.0 kN/m Elorpe 8.7 1.0 m V N9 S9 hg = 1.2m x/m Beamy onstud 1.5 m Silty Clay Cc/(1+e) = 0.13 3.5 m C/(1+e) = 0.04 = 17.8 kN/m^3 2.0 m fFnd C md comyarc if fo Clay Cc/(1+e) = 0.15 C/(1+e) = 0.05 = 400 kPa = 19.0 kN/m^3 3.0 m