00:01
Hello students, here from the question, they given that the data values are 246, 261, 267, 274, 277, 278, 282, 283, 284, 285, 286, 288, 289, 291, 292, 295, 296, 298, 312, and 502.
00:42
Here for the first one we need to find the outlier.
00:48
From the given data set, the outlier is 502 because it is there is a huge difference between the before value and the 502.
01:00
Then for this part b here we need to find the median.
01:08
Here for the formula for calculating median which is average of two middle values because here our n which is equal to 20.
01:27
So, the median which is 285 and 286 divided by 2 which we can get 285 .5 because 571 divided by 2.
01:45
This is our median.
01:47
Then for this apart c here we need to find the trimmed mean.
01:53
The trimmed mean is equal to sum of the remaining percentage of the sample.
02:11
Sum of remaining percentage of sample divided by the total remaining observation.
02:24
First here we need to calculate the untrimmed mean.
02:29
Then normal mean which is mean is equal to sum of all the observations we get here 5886 divided by 20 it is equal to 294 .3...